8x^2-8x-2.5=0

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Solution for 8x^2-8x-2.5=0 equation:



8x^2-8x-2.5=0
a = 8; b = -8; c = -2.5;
Δ = b2-4ac
Δ = -82-4·8·(-2.5)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-12}{2*8}=\frac{-4}{16} =-1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+12}{2*8}=\frac{20}{16} =1+1/4 $

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